Question

A. Assume that the GPA of college students in Luzon is approximately normally distributed. The

average GPA is 2.455 with a standard deviation of 0.66. Find the percentage of students who

obtained GPA below 1.25.

Answer 1

$$P(X<1.25)=P(Z<\dfrac{1.25-2.455}{0.66})$$

$$\approx P(Z<-1.8258)\approx0.0339$$

$3.39\%$