Question #344592

in the game of bridge each of 4 players is dealt 13 cars from an ordinary well-shuffled deck of 52 cards. Find the probability that one of the players gets a) 7 diamonds, 2 clubs, 3 hearts, and one spade, b) a complete suit, c) 9 cards are of one suit


1
Expert's answer
2022-05-25T14:26:39-0400

a)


P(7D & 2C & 3H & 1S)=(137)(132)(133)(131)(5213)P(7D\ \& \ 2C\ \&\ 3H \ \& \ 1S)=\dfrac{\dbinom{13}{7}\dbinom{13}{2}\dbinom{13}{3}\dbinom{13}{1}}{\dbinom{52}{13}}

=1716(286)(78)(13)635013559600=0.00078368=\dfrac{1716(286)(78)(13)}{635013559600}=0.00078368


b)


P(complete suit)=4(1313)(390)(5213)P(complete\ suit)=\dfrac{4\dbinom{13}{13}\dbinom{39}{0}}{\dbinom{52}{13}}

=4635013559600=6.3×1012=\dfrac{4}{635013559600}=6.3\times10^{-12}

c)


P(9 of one  suit)=4(139)(394)(5213)P(9\ of\ one\ \ suit)=\dfrac{4\dbinom{13}{9}\dbinom{39}{4}}{\dbinom{52}{13}}

=4(715)(82251)635013559600=0.00037045=\dfrac{4(715)(82251)}{635013559600}=0.00037045


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