Question #343954

. A quality controller wants to estimate the proportion of high quality goods out of a batch of products with a 90% confidence level and a margin of error of 5%. How many products must he test. 30


1
Expert's answer
2022-05-24T09:33:53-0400

A 90% confidence interval has a z-score (a critical value) zc=1.6449.z_c=1.6449.


ME=zc×p(1p)nME=z_c\times\sqrt{\dfrac{p(1-p)}{n}}

=1.6449×0.5(10.5)n=0.05=1.6449\times\sqrt{\dfrac{0.5(1-0.5)}{n}}=0.05

n=(16.449)2n=(16.449)^2

n=271n=271


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