Question

The final exam in statistics class were normally distributed with a mean of 63 and standard deviation of 5. Find the 90th percentile

Answer 1

The formula below is used to compute percentiles of a normal distribution.

$$x=\mu+z\sigma$$

Using $Z=1.2816$ the 90^th percentile is

$$x=63+1.2816\cdot 5=69.408$$