Suppose that the racial/ethnic distribution in a large city is given by the table that follows.
Black Hispanic Other
20% 15% 65%
Suppose that a jury of twelve members is chosen from this city in such a way that each resident has an equal probability of being selected independently of every other resident.
Lets find probability that the jury contains:
a. three Black, two Hispanic, and seven other members.
b. four Black and eight other members.
c. at most one Black member.
To solve this problem, let X=(X1,X2,X3)
where X1= number of Black members, X2= number of Hispanic members, and X3= number of Other members. Then X has a multinomial distribution with parameters n=12 and π=(0.20, 0.15, 0.65).
a. The answer to the first part is
b. The answer to the second part is
c. For the last part, note that "at most one Black member" means X1=0 or X1=1. X1 is a binomial random variable with n=12 and π1=0.2. Using the binomial probability distribution,
and
Therefore, the answer is:
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