Answer to Question #342792 in Statistics and Probability for Ahmad

Question #342792

Two chess players have the probability Player A would win is 0.40, Player B would win is 0.35, game would end in a draw is 0.25. If these two chess players played 12 games, what is the probability that Player A would win 7 games, Player B would win 2 games, the remaining 3 games would be drawn?


1
Expert's answer
2022-05-23T14:35:29-0400

Multinomial Distribution



"p=\\dfrac{n!}{(n_1)!(n_2)!(n_3)!}(p_1)^{n_1}(p_2)^{n_2}(p_3)^{n_3}"

Given

"n=12"

"n_1=7"

"n_2=2"

"n_3=3"

"p_1=0.40"

"p_2=0.35"

"p_3=0.25"



"p=\\dfrac{12!}{(7)!(2)!(3)!}(0.40)^{7}(0.35)^{2}(0.25)^{3}""=0.02483712"

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