Given: Margin of error (d)= 2.19, Confidence interval (CI) of population mean = 90%, and population standard deviation (σ)= 5 solve for the appropriate sample size.
The critical value for "\\alpha = 0.1" is "z_c = z_{1-\\alpha\/2} = 1.6449"
"n=(\\dfrac{z_c\\times \\sigma}{d})^2"
"n=(\\dfrac{1.6449\\times 5}{2.19})^2"
"n=14"
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