Question #341557

If Johnny had 20 complete living room outfits, disregard color scheme, how many different sets of five complete outfits could be arranged?  


Expert's answer

The number of possible sets is 


NCn=20C5=(205)=20!5!(205)!^{N}C_n=^{20}C_5=\dbinom{20}{5}=\dfrac{20!}{5!(20-5)!}

=20(19)(18)(17)(16)1(2)(3)(4)(5)=15504=\dfrac{20(19)(18)(17)(16)}{1(2)(3)(4)(5)}=15504


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