Answer to Question #341550 in Statistics and Probability for Zephyyy

Question

The Test score for a class are normally distributed . what is the the probability a student scored above 90

Answer 1

Given $\mu=75, \sigma=10.$

$$P(X>90)=1-P(Z\le\dfrac{90-75}{10})$$

$$=1-P(Z\le1.5)=0.0668$$