1 2 3 4 5 6 1 0 1 2 3 4 5 2 1 0 1 2 3 4 3 2 1 0 1 2 3 4 3 2 1 0 1 2 5 4 3 2 1 0 1 6 5 4 3 2 1 0 \def\arraystretch{1.5}
\begin{array}{c:c:c:c:c:c:c}
& 1 & 2 & 3 & 4 & 5 & 6 \\ \hline
1 & 0 & 1 & 2 & 3 & 4 & 5 \\
\hdashline
2 & 1 & 0 & 1 & 2 & 3 & 4 \\
\hdashline
3 & 2 & 1 & 0 & 1 & 2 & 3 \\
\hdashline
4 & 3 & 2 & 1 & 0 & 1 & 2 \\
\hdashline
5 & 4 & 3 & 2 & 1 & 0 & 1 \\
\hdashline
6 & 5 & 4 & 3 & 2 & 1 & 0 \\
\hdashline
\end{array} 1 2 3 4 5 6 1 0 1 2 3 4 5 2 1 0 1 2 3 4 3 2 1 0 1 2 3 4 3 2 1 0 1 2 5 4 3 2 1 0 1 6 5 4 3 2 1 0
1) The possible values of X X X are 0 , 1 , 2 , 3 , 4 , 0,1, 2, 3, 4, 0 , 1 , 2 , 3 , 4 , and 5. 5. 5.
2)
S = { 0 , 1 , 2 , 3 , 4 , 5 } S=\{0,1,2,3,4,5\} S = { 0 , 1 , 2 , 3 , 4 , 5 } 3)
x 0 1 2 3 4 5 p ( x ) 6 / 36 10 / 36 8 / 36 6 / 36 4 / 36 2 / 36 \def\arraystretch{1.5}
\begin{array}{c:c}
x & 0 & 1 & 2 & 3 & 4 & 5 \\ \hline
p(x) & 6/36 & 10/36 & 8/36 & 6/36 & 4/36 & 2/36 \\
\end{array} x p ( x ) 0 6/36 1 10/36 2 8/36 3 6/36 4 4/36 5 2/36
4)
f ( x ) = { 6 / 36 x = 0 10 / 36 x = 1 8 / 36 x = 2 6 / 36 x = 3 4 / 36 x = 4 2 / 36 x = 5 f(x) = \begin{cases}
6/36 &\ x=0 \\
10/36&\ x=1 \\
8/36&\ x=2 \\
6/36&\ x=3 \\
4/36&\ x=4 \\
2/36&\ x=5 \\
\end{cases} f ( x ) = ⎩ ⎨ ⎧ 6/36 10/36 8/36 6/36 4/36 2/36 x = 0 x = 1 x = 2 x = 3 x = 4 x = 5
5)
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