The number of possible samples which can be selected without replacement is
NCn=N!n!⋅(N−n)!;_NC_n=\cfrac{N! } {n! \cdot(N-n)! };NCn=n!⋅(N−n)!N!;
5C3=5!3!⋅(5−3)!=4⋅52=10._{5}C_3=\cfrac{5! } {3! \cdot(5-3)! }=\cfrac{4\cdot5}{2}=10.5C3=3!⋅(5−3)!5!=24⋅5=10.
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments