Question #33913

1.Two cards are drawn from a deck, at random, in succession and without replacement.
a.What is the probability that the first draw is an ace?
b.What is the probability that both the first and the second draws are aces?
1

Expert's answer

2013-08-15T08:45:39-0400

Task. Two cards are drawn from a deck, at random, in succession and without replacement.

a. What is the probability that the first draw is an ace?

b. What is the probability that both the first and the second draws are aces?

Solution. Recall that the deck contains 52 cards and 4 aces among them.

a) Since two cards are drawn from a deck, at random, in succession and without replacement, the probability that first card is ace does not depend on the second card. So the probability that the first draw is an ace is equal to

p=number of acestotal number of cards=452=1130.076923.p=\frac{\text{number of aces}}{\text{total number of cards}}=\frac{4}{52}=\frac{1}{13}\approx 0.076923.

b) The number of pairs among 52 cards is equal to

C522=52!2!(522)!=52!2!50!=52512=1326.C_{52}^{2}=\frac{52!}{2!(52-2)!}=\frac{52!}{2!50!}=\frac{52*51}{2}=1326.

The number of pairs among 4 aces is

C42=4!2!2!=244=6.C_{4}^{2}=\frac{4!}{2!2!}=\frac{24}{4}=6.

Hence the probability that both the first and the second draws are aces is equal to

p=number of pairs among 4 cardsnumber of pairs among 52 cards=61326=1221=0.0045249.p=\frac{\text{number of pairs among 4 cards}}{\text{number of pairs among 52 cards}}=\frac{6}{1326}=\frac{1}{221}=0.0045249.

Answer.


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