Question #339128

Find the probability of z lying between z=0 and z=2.3.


1
Expert's answer
2022-05-11T09:44:18-0400
P(0<Z<2.3)=P(Z<2.3)−P(Z≤0)P(0<Z<2.3)=P(Z<2.3)-P(Z\le 0)

=0.9893−0.5=0.4893=0.9893-0.5=0.4893


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Guyana #340795 on Jan 2024