the waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between 0 and 8 minutes. Find the probability that a randomly selected passenger has a waiting time greater than 4.25 minutes
We have a uniform distribution, a=0, b=8.
The probability that X takes on a value between x1 and x2 can be found by the following formula:
"P(x_1<X<x_2)=\\cfrac{x_2-x_1}{b-a},\\\\\nP(4.25<X<8)=\\cfrac{8-4.25}{8-0}=0.46875."
Comments
Leave a comment