Question #337513

A population consists of the four number (2,3,6,9).

Consider all possible samples of size 2 that can be drawn with replacement from this population. Answer the following:


a. List all possible samples of size 2 which can be drawn with replacement from this population.

b. Compute the Population mean.

c. Compute the Population Standard deviation.

d. Find the mean of the sampling distribution.



Expert's answer

a. The number of possible samples which can be selected with replacement is

Nn=42=16.N^n=4^2=16.

All the possible samples of sizes n=2 wich can be drawn with replacement from the population:

{(2,2),(2,3),(2,6),(2,9),(3,2),(3,3),(3,6),(3,9),(6,2),(6,3),(6,6),(6,9),(9,2),(9,3),(9,6),(9,9)}.\{ (2,2), (2,3),(2,6),(2,9),\\ (3,2),(3,3),(3,6),(3,9),\\ (6,2), (6,3),(6,6),(6,9),\\ (9,2),(9,3),(9,6),(9,9)\}.


b. The population mean:

μ=2+3+6+94=5.\mu=\cfrac{2+3+6+9}{4}=5.


c. The population variance:

σ2=(xiμ)2P(xi),\sigma^2=\sum(x_i-\mu)^2\cdot P(x_i),

Xμ={25,35,65,95}=X-\mu=\begin{Bmatrix} 2-5,3-5,6-5,9-5 \end{Bmatrix}=

={3,2,1,4},=\begin{Bmatrix} -3, - 2,1,4 \end{Bmatrix},

σ2=(3)214+(2)214++1214+4214=7.5.\sigma^2=(-3)^2\cdot \cfrac{1}{4}+(-2)^2\cdot \cfrac{1}{4}+\\ +1^2\cdot \cfrac{1}{4}+4^2\cdot \cfrac{1}{4}=7.5.

The population standard deviation:

σ=7.5=2.739.\sigma=\sqrt{7.5}=2.739.


d. The mean of the sampling distribution of sample means:

μxˉ=μ=5.\mu_{\bar x} =\mu=5.




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