Question #336755

Test the hypotheses, given p=0.42, p is not equal to 0.42, sample size=150, sample proportion=0.45, alpha =0.05


1
Expert's answer
2022-05-04T13:23:42-0400

The following null and alternative hypotheses for the population proportion needs to be tested:

p=0.42p=0.42

p0.42p\not=0.42

This corresponds to a two-tailed test, for which a z-test for one population proportion will be used.

Based on the information provided, the significance level is α=0.05,\alpha = 0.05, and the critical value for a two-tailed test is zc=1.96.z_c = 1.96.

The rejection region for this two-tailed test is R={z:z>1.96}.R = \{z: |z| > 1.96\} .

The z-statistic is computed as follows:


z=p^p0p0(1p0)n=0.450.420.42(10.42)150z=\dfrac{\hat{p}-p_0}{\sqrt{\dfrac{p_0(1-p_0)}{n}}}=\dfrac{0.45-0.42}{\sqrt{\dfrac{0.42(1-0.42)}{150}}}

0.7444\approx0.7444

Since it is observed that z=0.7441.96=zc,|z| = 0.744 \le1.96= z_c , it is then concluded that the null hypothesis is not rejected.

Using the P-value approach:

The p-value is p=2P(Z>1.7444)=0.456635,p =2 P(Z>1.7444)=0.456635, and since p=0.456635>0.05=α,p = 0.4566 35>0.05=\alpha, it is concluded that the null hypothesis is not rejected.

Therefore, there is not enough evidence to claim that the population proportion pp is different than 0.42, at the α=0.05\alpha = 0.05 significance level.


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