Answer to Question #336636 in Statistics and Probability for Bob

Question

A random variable x is normally with mean 10 and variance 6.25 what is the value of p(x>12.25)

Answer 1

$$P(X>12.25)=1-P(Z\le\dfrac{12.25-10}{\sqrt{6.25}})$$

$$=1-P(Z\le0.9)\approx0.184060$$