Answer to Question #336636 in Statistics and Probability for Bob

Statistics and Probability

Question #336636

A random variable x is normally with mean 10 and variance 6.25 what is the value of p(x>12.25)

Expert's answer

"P(X>12.25)=1-P(Z\\le\\dfrac{12.25-10}{\\sqrt{6.25}})"

"=1-P(Z\\le0.9)\\approx0.184060"

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