Answer to Question #336618 in Statistics and Probability for Rival

Question

An American Society of Investors survey found 30% of individual investors have used a discount broker. In a random sample of nine individuals, what is the probability:

a. Exactly two of the sampled individuals have used a discount broker?

b. Exactly four of them have used a discount broker?

c. None of them has used a discount broker? 

Answer 1

We have a Bernoulli trial - exactly two possible outcomes, "success" (the individual investor has used a discount broker) and "failure" (the individual investor hasn't used a discount broker) and the probability of success is the same every time the experiment is conducted (an individual investor is examined), p=0.3,q=1−p=1−0.3=0.7, n=9.

The probability of each result

$P(X=k)=\begin{pmatrix}n\\k\end{pmatrix}\cdot p^k\cdot q^{n-k}=\\ =\begin{pmatrix}9\\k\end{pmatrix}\cdot 0.3^k\cdot 0.7^{9-k}=\\ =\cfrac{9!}{k!\cdot(9-k)!}\cdot 0.3^k\cdot 0.7^{9-k}.$

$\text{a. } P(X=2)=\cfrac{9!}{2!\cdot7!}\cdot 0.3^{2}\cdot 0.7^{7}=0.2668.\\ \text{b. } P(X=4)=\cfrac{9!}{4!\cdot5!}\cdot 0.3^{4}\cdot 0.7^{5}=0.1715.\\ \text{c. } P(X=0)=\cfrac{9!}{0!\cdot9!}\cdot 0.3^{0}\cdot 0.7^{9}=0.0404.\\$