Question #336392

Suppose that 9 good fuses and 4 defective ones have been mixed up. To find the defective fuses, we test them one-by-one, at random. What is the probability that we are lucky and find both of the defective fuses in the first two tests?


1). With replacement


2). Without replacement


Expert's answer

1)


P(both defective)=49+4(49+4)=16169P(both\ defective)=\dfrac{4}{9+4}(\dfrac{4}{9+4})=\dfrac{16}{169}

2)


P(both defective)=49+4(4−19+4−1)=113P(both\ defective)=\dfrac{4}{9+4}(\dfrac{4-1}{9+4-1})=\dfrac{1}{13}


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