Answer to Question #336081 in Statistics and Probability for Petty

Statistics and Probability

Question #336081

X-N(45, variance) and p(x>51)=0.288 find standard deviation

Expert's answer

"P(X>51)=1-P(Z\\le\\dfrac{51-45}{\\sigma})=0.288"

"\\dfrac{51-45}{\\sigma}=0.559237"

"\\sigma=\\dfrac{6}{0.559237}\\approx10.7289"

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