Answer to Question #336003 in Statistics and Probability for Shahid

Question

limh→ 0 (6+h)

2−36

h

Answer 1

$$\lim\limits_{h\to 0}\dfrac{(6+h)^2-36}{h}=\lim\limits_{h\to 0}\dfrac{36+12h+h^2-36}{h}$$

$$=\lim\limits_{h\to 0}(12+h)=12+0=12$$