Question

Use the standard normal probability table to find the value z for each of the following.

(a) P (0≤Z≤z) = 0.41 (b) P(Z≥z) = 0.25

(c) P (Z≤z)= 0.95 (d) P(-z≤Z≤z) = 0.88

Answer 1

(a) $P (0≤Z≤z) = 0.41$

$$P (Z≤z) = 0.41+0.5$$

$$z=1.340755$$

(b) $P (Z\ge z) = 0.25$

$$z=0.674490$$

(c) $P (Z≤z) = 0.95$

$$z=1.644854$$

(d)$P(-z≤Z≤z) = 0.88$

$$P(Z\ge z) = 0.06$$

$$z=1.554773$$