Answer to Question #334894 in Statistics and Probability for denden

Question

In a plant box consisting of 120 seedlings, 80 seedlings were treated with growth enhancer. Estimate p and q. What is the Point Estimate and Standard Deviation?

Answer 1

$p=\dfrac{80}{120}=\dfrac{2}{3}$

$q=1-p=1-\dfrac{2}{3}=\dfrac{1}{3}$

Point Estimate

$\mu=np=120(\dfrac{2}{3})=80$

Standard Deviation

$\sigma=\sqrt{npq}=\sqrt{120(\dfrac{2}{3})(\dfrac{1}{3})}=\dfrac{4\sqrt{15}}{3}$