Question

A basket has 12 marigolds and 8 carnations. if we had picked two flowers one by one with replacement, find the probability of getting a marigold and a carnation.

Answer 1

$$P(MC)=\dfrac{12}{12+8}(\dfrac{8}{12+8})=0.24$$

$$P(CM)=\dfrac{8}{12+8}(\dfrac{12}{12+8})=0.24$$

$$P(M\ and \ C)=P(MC)+P(CM)$$

$$=0.24+0.24=0.48$$

The probability of getting a marigold and a carnation is 0.48.