Answer to Question #333783 in Statistics and Probability for Laurie

Question #333783

A basket has 12 marigolds and 8 carnations. if we had picked two flowers one by one with replacement, find the probability of getting a marigold and a carnation.

Expert's answer

P(MC)=\dfrac{12}{12+8}(\dfrac{8}{12+8})=0.24

P(CM)=\dfrac{8}{12+8}(\dfrac{12}{12+8})=0.24

P(M\ and \ C)=P(MC)+P(CM)

=0.24+0.24=0.48

The probability of getting a marigold and a carnation is 0.48.

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