The mean height of the grade nine students at a certain high school is 164 centimeters and the
standard deviation is 10 centimeters. Assuming the heights are normally distributed, what
percent of the heights is greater than 168 centimeters?
We have a normal distribution, "\\mu=164, \\sigma=10."
Let's convert it to the standard normal distribution,
"z=\\cfrac{x-\\mu}{\\sigma}=\\cfrac{168-164}{10}=0.40;"
"P(X>168)=P(Z>0.40)=\\\\\n=1-P(Z<0.40)=\\\\\n=1-0.6554=0.3446=34.46\\%\\text{ (from z-table)}."
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