Question #332246

The Smith Trucking Company claims that the average weight of its delivery






trucks when fully loaded is 6000 pounds with a standard deviation of 120






pounds. 36 trucks are selected at random and their weights recorded.






Within what limits will the average weights of 90% of the 36 trucks lie?

1
Expert's answer
2022-04-24T18:04:55-0400

We have a normal distribution,

xˉ=6000,σ=120,n=36.\bar x=6000,\sigma=120, n=36.


The formula to calculate a confidence interval for a population mean is as follows:

CI=xˉ±zσn,CI=\bar{x}\pm z\cdot\cfrac{\sigma}{\sqrt{n}},

where:

  • xˉ=6000\bar{x}=6000- sample mean
  • z- the chosen z-value, for a 90% confidence interval z = 1.645
  • σ=120\sigma=120- sample standard deviation
  • n =36 - sample size.


So,

CI=6000±1.64512036==6000±32.9=(5967.1,6032.9).CI=6000 \pm 1.645\cdot\cfrac{120}{\sqrt{36}}=\\=6000\pm32.9=(5967.1, 6032.9).





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