Question #332024

A population consists of three numbers (3,6,9).Consider all possible samples of size n=2 which can be drawn WITHOUT REPLACEMENT from the population.

Questions to be answered:

Population mean

Population variance

Population standard deviation

Mean of the sampling distribution of the means

Variance of the sampling distributionof the means

Standard deviation of the sampling distribution of the means


1
Expert's answer
2022-04-22T13:11:33-0400


Population mean:

μ=3+6+93=6.\mu=\cfrac{3+6+9}{3}=6.


Population variance:

σ2=(xiμ)2P(xi),\sigma^2=\sum(x_i-\mu)^2\cdot P(x_i),

Xμ={36,66,96}=X-\mu=\begin{Bmatrix} 3-6,6-6, 9-6 \end{Bmatrix}=

={3,0,3},=\begin{Bmatrix} -3, 0,3 \end{Bmatrix},

σ2=(3)213+0213+3213=6.\sigma^2=(-3)^2\cdot \cfrac{1}{3}+0^2\cdot \cfrac{1}{3}+3^2\cdot \cfrac{1}{3}=6.


Population standard deviation:

σ=6=2.449.\sigma=\sqrt{6}=2.449.


Mean of the sampling distribution of sample means:

μxˉ=μ=6.\mu_{\bar x} =\mu=6.


Variance of the sampling distribution of sample means:

σxˉ2=σ2n=62=3.\sigma^2_{\bar x}=\cfrac{\sigma^2}{n}=\cfrac{6}{2}=3.


Standard deviation of the sampling distribution of sample means:

σxˉ=σn=62=1.732.\sigma_{\bar x}=\cfrac{\sigma}{\sqrt n}=\cfrac{\sqrt 6}{\sqrt 2}=1.732.



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