X= 842, n= 1200, 95% CONFIDENCE
p^=8421200=\hat p=\frac{842}{1200}=p^=1200842= 0.0702.
95%CI=(0.0702−1.960.0702(1−0.0702)1200,0.0702+1.960.0702(1−0.0702)1200)=95\%CI=(0.0702-1.96\sqrt{\frac{0.0702(1-0.0702)}{1200}},0.0702+1.96\sqrt{\frac{0.0702(1-0.0702)}{1200}})=95%CI=(0.0702−1.9612000.0702(1−0.0702),0.0702+1.9612000.0702(1−0.0702))=
=(0.6758,0.7276).=(0.6758,0.7276).=(0.6758,0.7276).
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