Question #331769

X= 842, n= 1200, 95% CONFIDENCE


1
Expert's answer
2022-04-22T02:55:36-0400

p^=8421200=\hat p=\frac{842}{1200}= 0.0702.

95%CI=(0.07021.960.0702(10.0702)1200,0.0702+1.960.0702(10.0702)1200)=95\%CI=(0.0702-1.96\sqrt{\frac{0.0702(1-0.0702)}{1200}},0.0702+1.96\sqrt{\frac{0.0702(1-0.0702)}{1200}})=

=(0.6758,0.7276).=(0.6758,0.7276).


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