Question #331430

A researcher claims that the average salary of a private school teacher is greater than P35,000 with



a standard deviation of P7,000. A sample of 35 teachers has a mean salary of P37,000. Test the



claim of the researcher. At 0.05 level of significance, test the claim of the researcher.

1
Expert's answer
2022-04-27T13:53:53-0400

The following null and alternative hypotheses need to be tested:

H0:μ35000H_0:\mu\le35000

H1:μ>35000H_1:\mu>35000

This corresponds to a right-tailed test, for which a t-test for one mean, with unknown population standard deviation, using the sample standard deviation, will be used.

Based on the information provided, the significance level is α=0.05,\alpha=0.05, df=n1=351=34df=n-1=35-1=34 degrees of freedom, and the critical value for a right-tailed test is tc=1.690924.t_c = 1.690924.

The rejection region for this right-tailed test is R={t:t>1.690924}.R = \{t: t> 1.690924\}.

The t-statistic is computed as follows:


t=xˉμs/n=37000350007000/351.6903t=\dfrac{\bar{x}-\mu}{s/\sqrt{n}}=\dfrac{37000-35000}{7000/\sqrt{35}}\approx1.6903

Since it is observed that t=1.6903<1.690924=tc,t =1.6903 <1.690924=t_c, it is then concluded that the null hypothesis is not rejected.

Using the P-value approach:

The p-value for right-tailed, df=34df=34 degrees of freedom, t=1.6903t=1.6903 is p=0.05006,p=0.05006, and since p=0.05006>0.05=α,p=0.05006>0.05=\alpha, it is concluded that the null hypothesis is not rejected.

Therefore, there is not enough evidence to claim that the population mean μ\mu

is greater than 35000, at the α=0.05\alpha = 0.05 significance level.


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