Question #331430

A researcher claims that the average salary of a private school teacher is greater than P35,000 with



a standard deviation of P7,000. A sample of 35 teachers has a mean salary of P37,000. Test the



claim of the researcher. At 0.05 level of significance, test the claim of the researcher.

Expert's answer

The following null and alternative hypotheses need to be tested:

H0:μ35000H_0:\mu\le35000

H1:μ>35000H_1:\mu>35000

This corresponds to a right-tailed test, for which a t-test for one mean, with unknown population standard deviation, using the sample standard deviation, will be used.

Based on the information provided, the significance level is α=0.05,\alpha=0.05, df=n1=351=34df=n-1=35-1=34 degrees of freedom, and the critical value for a right-tailed test is tc=1.690924.t_c = 1.690924.

The rejection region for this right-tailed test is R={t:t>1.690924}.R = \{t: t> 1.690924\}.

The t-statistic is computed as follows:


t=xˉμs/n=37000350007000/351.6903t=\dfrac{\bar{x}-\mu}{s/\sqrt{n}}=\dfrac{37000-35000}{7000/\sqrt{35}}\approx1.6903

Since it is observed that t=1.6903<1.690924=tc,t =1.6903 <1.690924=t_c, it is then concluded that the null hypothesis is not rejected.

Using the P-value approach:

The p-value for right-tailed, df=34df=34 degrees of freedom, t=1.6903t=1.6903 is p=0.05006,p=0.05006, and since p=0.05006>0.05=α,p=0.05006>0.05=\alpha, it is concluded that the null hypothesis is not rejected.

Therefore, there is not enough evidence to claim that the population mean μ\mu

is greater than 35000, at the α=0.05\alpha = 0.05 significance level.


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