Construct the sampling distribution
1. A population consists of the values 1,4,3,2 with sample size 2.
2. A population consists of 1,3,5,7,9 with sample size 3.
1. m(1,4)= (1+4)/2=2.5
m(1,3)=(1+3)/2=2
m(1,2)=(1+2)/2=1.5
m(2,3)=(2+3)/2=2.5
m(2,4)=(2+4)/2=3
m(3,4)=(3+4)/2=3.5
Frequency F(2)=F(1.5)=F(3)=F(3.5)=1
F(2.5)=2
Probability "P(x)=F(x)\/\\sum F(x)"
P(2)=P(1.5)=P(3)=P(3.5)=1/6
P(2.5)=2/6=1/3
2.
m(1,3,5)=(1+3+5)/3=3
m(1,3,7)=(1+7+3)/3=3.7
m(1,3,9)=(1+3+9)/3=4.3
m(1,5,9)=(1+5+9)/3=5
m(1,5,7)=(1+5+7)/3=4.3
m(1,7.9)=(1+7+9)/3=5.7
m(3,5,7)=(3+5+7)/3=5
m(3,5,9)=(3+5+9)/3=5.7
m(3,7,9)=(3+7+9)/3=6.3
m(5,7,9)=(5+7+9)/3=7
Frequency F(3)=F(3.7)=F(6.3)=F(7)=1
F(4.3)=F(5.7)=F(5)=2
Probabilitys "P(x)=F(x)\/\\sum F(x)"
P(3)=P(3.7)=P(6.3)=P(7)=0.1
P(4.3)=P(5.7)=P(5)=0.2
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