Question #331316

random variable X has this probability distribution:


x 0 1 2 3 4 5


P(X=x) 0.1 0.2 0.05 0.1 ? 0.3


Find f(4)



1
Expert's answer
2022-04-21T03:23:49-0400

The sum of all probabilities for different values of xx must be equal to 1.1. We receive: x=05P(X=x)=1\sum_{x=0}^5P(X=x)=1. From the latter we get: 0.1+0.2+0.05+0.1+0.3+P(X=4)=10.1+0.2+0.05+0.1+0.3+P(X=4)=1. We receive: 0.75+P(X=4)=1;0.75+P(X=4)=1; P(X=4)=0.25P(X=4)=0.25. In case we denote: f(x)=P(X=x)f(x)=P(X=x), we get: f(4)=P(X=4)=0.25.f(4)=P(X=4)=0.25.


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