Question #331267

SOLVE THE FOLLOWING:



1. A random variable X has this probability distribution:



x 0 1 2 3 4 5



P(X=x) 0.1 0.2 0.05 0.1 ? 0.3





1
Expert's answer
2022-04-20T14:46:01-0400

The sum of probabilities for all values of xx must be equal to 11. Thus, we get: x=05P(X=x)=1\sum_{x=0}^5P(X=x)=1. We receive: 0.1+0.2+0.05+0.1+0.3+P(X=4)=10.1+0.2+0.05+0.1+0.3+P(X=4)=1. We get: 0.75+P(X=4)=10.75+P(X=4)=1. Thus, we get P(X=4)=0.25P(X=4)=0.25.


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