Question

Diameters of bolts produced by a particular machine are normally distributed

with mean 0.760 cm and standard deviation 0.012 cm. Specifications call for

diameters from 0.720 cm to 0.780 cm.

Answer 1

$P(0.720<X<0.780)=P(\frac{0.720-0.760}{0.012}<Z<\frac{0.780-0.760}{0.012})=P(-3.33<Z<1.66)=0.9515-0.00043=0.95107$