What is the corresponding z – score value when its area in the normal curve is 0.2123? Use the z- table to find the value
From z-table we find the closest value to 0.2123; it is 0.2119 and the corresponding z-score is z=−0.80;z=-0.80;z=−0.80;
P(z<−0.80)=0.2119.P(z<-0.80)=0.2119.P(z<−0.80)=0.2119.
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