We have a normal distribution, μ=20,σ=3.5.
Let's convert it to the standard normal distribution,
z=σx−μ.
a. z=3.516−20=−1.14;P(X<16)=P(Z<−1.14)==0.1271.
b. z=3.522.5−20=0.71;P(X>22.5)=P(Z>0.71)==1−P(Z<0.71)==1−0.7611=0.2389.
c. z1=3.514−20=−1.71;z2=3.523.5−20=1;P(14<X<23.5)=P(−1.71<Z<1)==P(Z<1)−P(Z<−1.71)==0.8413−0.0436=0.7977.
d. z1=3.511−20=−2.57;z2=3.515−20=−1.43;P(11<X<15)=P(−2.57<Z<−1.43)==P(Z<−1.43)−P(Z<−2.57)==0.0764−0.0051=0.0713 (from z-table).
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