Consider a population consisting of the values (1, 3, 8), n= 2 with replacement.
There are 32=9samples,the probability of each is 19There\,\,are\,\,3^2=9 samples, the\,\,probability\,\,of\,\,each\,\,is\,\,\frac{1}{9}Thereare32=9samples,theprobabilityofeachis91
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