a : 630 ⋅ 0.384 = 241.92 ≈ 242 b : L B = p ^ − p ^ ( 1 − p ^ ) n z 1 + γ 2 = 0.384 − 0.384 ( 1 − 0.384 ) 630 ⋅ 2.5758 = 0.334089 U B = p ^ + p ^ ( 1 − p ^ ) n z 1 + γ 2 = 0.384 + 0.384 ( 1 − 0.384 ) 630 ⋅ 2.5758 = 0.433911 c : L B = p ^ − p ^ ( 1 − p ^ ) n z 1 + γ 2 = 0.384 − 0.384 ( 1 − 0.384 ) 630 ⋅ 1.6449 = 0.352127 U B = p ^ + p ^ ( 1 − p ^ ) n z 1 + γ 2 = 0.384 + 0.384 ( 1 − 0.384 ) 630 ⋅ 1.6449 = 0.415873 d : T h e 99 % i n t e r v a l i s w i d e r b e c a u s e t h e w i d e r i n t e r v a l t h e h i g h e r p r o b a b i l i t y . a:\\630\cdot 0.384=241.92\approx 242\\b:\\LB=\hat{p}-\sqrt{\frac{\hat{p}\left( 1-\hat{p} \right)}{n}}z_{\frac{1+\gamma}{2}}=0.384-\sqrt{\frac{0.384\left( 1-0.384 \right)}{630}}\cdot 2.5758=0.334089\\UB=\hat{p}+\sqrt{\frac{\hat{p}\left( 1-\hat{p} \right)}{n}}z_{\frac{1+\gamma}{2}}=0.384+\sqrt{\frac{0.384\left( 1-0.384 \right)}{630}}\cdot 2.5758=0.433911\\c:\\LB=\hat{p}-\sqrt{\frac{\hat{p}\left( 1-\hat{p} \right)}{n}}z_{\frac{1+\gamma}{2}}=0.384-\sqrt{\frac{0.384\left( 1-0.384 \right)}{630}}\cdot 1.6449=0.352127\\UB=\hat{p}+\sqrt{\frac{\hat{p}\left( 1-\hat{p} \right)}{n}}z_{\frac{1+\gamma}{2}}=0.384+\sqrt{\frac{0.384\left( 1-0.384 \right)}{630}}\cdot 1.6449=0.415873\\d:\\The\,\,99\% interval\,\,is\,\,wider\,\,because\,\,the\,\,wider\,\,interval\,\,the\,\,higher\,\,probability. a : 630 ⋅ 0.384 = 241.92 ≈ 242 b : L B = p ^ − n p ^ ( 1 − p ^ ) z 2 1 + γ = 0.384 − 630 0.384 ( 1 − 0.384 ) ⋅ 2.5758 = 0.334089 U B = p ^ + n p ^ ( 1 − p ^ ) z 2 1 + γ = 0.384 + 630 0.384 ( 1 − 0.384 ) ⋅ 2.5758 = 0.433911 c : L B = p ^ − n p ^ ( 1 − p ^ ) z 2 1 + γ = 0.384 − 630 0.384 ( 1 − 0.384 ) ⋅ 1.6449 = 0.352127 U B = p ^ + n p ^ ( 1 − p ^ ) z 2 1 + γ = 0.384 + 630 0.384 ( 1 − 0.384 ) ⋅ 1.6449 = 0.415873 d : T h e 99% in t er v a l i s w i d er b ec a u se t h e w i d er in t er v a l t h e hi g h er p ro babi l i t y .
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