Question #329419

The value of serum sodium in healthy adults approximately follows a normal distribution with a mean of 141meq/l and standard deviation of 3meq/l


(a) What is the probability that a normal healthy adult will have a serum sodium value above 147meq/l ( 5 marks)


(b) What is the probability that a normal healthy adult will have a serum sodium value below 130 meq/l ( 5 marks)


(c) What is the probability that a normal healthy adult will have a serum sodium value between 132 and 150meq/l (5 marks)

1
Expert's answer
2022-04-18T00:11:42-0400

We have a normal distribution, μ=141,σ=3.\mu=141, \sigma=3.

Let's convert it to the standard normal distribution,

z=xμσ.z=\cfrac{x-\mu}{\sigma}.


(a) z=1471413=2;P(X>147)=P(Z>2)==1P(Z<2)==10.9772=0.0228 (from z-table).(a) \ z=\cfrac{147-141}{3}=2;\\ P(X>147)=P(Z>2)=\\ =1-P(Z<2)=\\ =1-0.9772=0.0228 \text{ (from z-table).}


(b) z=1301413=3.67;P(X<130)=P(Z<3.67)==0.0001 (from z-table).(b) \ z=\cfrac{130-141}{3}=-3.67;\\ P(X<130)=P(Z<-3.67)=\\ =0.0001 \text{ (from z-table).}


(c) z1=1321413=3;z2=1501413=3;P(132<X<150)=P(3<Z<3)==P(Z<3)P(Z<3)==0.99870.0013=0.9974 (from z-table).(c) \ z_1=\cfrac{132-141}{3}=-3;\\ z_2=\cfrac{150-141}{3}=3;\\ P(132<X<150)=P(-3<Z<3)=\\ =P(Z<3)-P(Z<-3)=\\ =0.9987-0.0013=0.9974 \text{ (from z-table).}

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