Answer to Question #327616 in Statistics and Probability for sasas

Question #327616

Given a normal distribution with a mean of 200 and the deviation is10. Find the area above 188.

Expert's answer

"P(X>188)=P(Z>\\frac{188-200}{10})=P(Z>-1.2)=1-P(Z<-1.2)=0.8849."

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