The scores in the summative test of 11-ABM A are normally distributed with a mean of 65 and a standard deviation of 12. Illustrate a normal curve and find the probability that some students got a score below 40. (Show your solution)
Normal curve
P(X<40)=P(N(65,122)<40)=P(65+12N(0,1)<40)=P(N(0,1)<−2.08)=0.01861P(X<40)=P(N(65,12^2)<40)=P(65+12N(0,1)<40)=P(N(0,1)<-2.08)=0.01861P(X<40)=P(N(65,122)<40)=P(65+12N(0,1)<40)=P(N(0,1)<−2.08)=0.01861
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