Answer to Question #327154 in Statistics and Probability for Karya

Statistics and Probability

Question #327154

The area between z=0 and z=2.86

Expert's answer

"P(0<Z<2.86)=\\\\\n=P(Z<2.86)-P(Z<0)=\\\\\n=0.9979-0.5000=0.4979 \\text{ (from z-table).}"

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