In a Math test, the mean score is 48 and the standard deviation is 7. Assuming normality, what is probability that a score picked at random will lie above score 55?
P(X>55)=P(Z>55−487)=P(Z>1)=1−P(Z<1)=0.1587.P(X>55)=P(Z>\frac{55-48}{7})=P(Z>1)=1-P(Z<1)=0.1587.P(X>55)=P(Z>755−48)=P(Z>1)=1−P(Z<1)=0.1587.
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