Question #325990

Random samples of size N=2 are drawn from a finite population consisting of the number 5,6,7,8, and 9. Compute for the mean, Variance,and Standard deviation, and also the mean, Variance, and the Standard deviation of the sample mean

Expert's answer

The population mean:

μ=5+6+7+8+95=7.\mu=\cfrac{5+6+7+8+9}{5}=7.


The population variance:

σ2=(xiμ)2P(xi),\sigma^2=\sum(x_i-\mu)^2\cdot P(x_i),

Xμ={57,67,77,87,97}=X-\mu=\begin{Bmatrix} 5-7,6-7,7-7, 8-7,9-7 \end{Bmatrix}=

={2,1,0,1,2},=\begin{Bmatrix} -2, -1, 0, 1,2 \end{Bmatrix},

σ2=(2)215+(1)215+0215++1215+2215=2.\sigma^2=(-2)^2\cdot \cfrac{1}{5}+(-1)^2\cdot \cfrac{1}{5}+0^2\cdot \cfrac{1}{5}+\\ +1^2\cdot \cfrac{1}{5}+2^2\cdot \cfrac{1}{5}=2.


The population standard deviation:

σ=2=1.414.\sigma=\sqrt{2}=1.414.


The mean of the sampling distribution of sample means:

μxˉ=μ=7.\mu_{\bar x} =\mu=7.


The variance of the sampling distribution of sample means:

σxˉ2=σ2n=22=1.\sigma^2_{\bar x}=\cfrac{\sigma^2}{n}=\cfrac{2}{2}=1.


The standard deviation of the sampling distribution of sample means:

σxˉ=σn=22=1.\sigma_{\bar x}=\cfrac{\sigma}{\sqrt n}=\cfrac{\sqrt 2}{\sqrt 2}=1.

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