Question #325990

Random samples of size N=2 are drawn from a finite population consisting of the number 5,6,7,8, and 9. Compute for the mean, Variance,and Standard deviation, and also the mean, Variance, and the Standard deviation of the sample mean

1
Expert's answer
2022-04-11T10:05:03-0400

The population mean:

μ=5+6+7+8+95=7.\mu=\cfrac{5+6+7+8+9}{5}=7.


The population variance:

σ2=(xiμ)2P(xi),\sigma^2=\sum(x_i-\mu)^2\cdot P(x_i),

Xμ={57,67,77,87,97}=X-\mu=\begin{Bmatrix} 5-7,6-7,7-7, 8-7,9-7 \end{Bmatrix}=

={2,1,0,1,2},=\begin{Bmatrix} -2, -1, 0, 1,2 \end{Bmatrix},

σ2=(2)215+(1)215+0215++1215+2215=2.\sigma^2=(-2)^2\cdot \cfrac{1}{5}+(-1)^2\cdot \cfrac{1}{5}+0^2\cdot \cfrac{1}{5}+\\ +1^2\cdot \cfrac{1}{5}+2^2\cdot \cfrac{1}{5}=2.


The population standard deviation:

σ=2=1.414.\sigma=\sqrt{2}=1.414.


The mean of the sampling distribution of sample means:

μxˉ=μ=7.\mu_{\bar x} =\mu=7.


The variance of the sampling distribution of sample means:

σxˉ2=σ2n=22=1.\sigma^2_{\bar x}=\cfrac{\sigma^2}{n}=\cfrac{2}{2}=1.


The standard deviation of the sampling distribution of sample means:

σxˉ=σn=22=1.\sigma_{\bar x}=\cfrac{\sigma}{\sqrt n}=\cfrac{\sqrt 2}{\sqrt 2}=1.

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