let x be a binomial random variable. use the formula to compute the following probabilities;
(a) p(x=2), if n=8 and p=0.1
(b) p(x=5), if n=9 and p=0.5
(c) p(x=9), if n=10 and p=0.95
"P_x=C^x_np^xq^{n-x}"
a.q=1-p=0.9
"C^2_80.1^20.9^6=\\frac{8!}{2!6!}0.01x0.531441=0.1488"
b. "C^5_90.5^50.5^4=\\frac{9!}{5!4!}0.03125x0.0625=0.246"
c.
"C^9_{10}0.95^90.05^1=\\frac{10!}{9!1!}0.63x0.05=0.315"
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