In a Science test, the mean score is 42 and the standard deviation is 5. Assuming the scores are normally distributed, what percent of the score is:
Less than 50?
We have a normal distribution, μ=42,σ=5.\mu=42, \sigma=5.μ=42,σ=5.
Let's convert it to the standard normal distribution,
z=x−μσ=50−425=1.60;P(X<50)=P(Z<1.60)==0.9452=94.52% (from z-table).z=\cfrac{x-\mu}{\sigma}=\cfrac{50-42}{5}=1.60;\\ P(X<50)=P(Z<1.60)=\\ =0.9452=94.52\% \text{ (from z-table).}z=σx−μ=550−42=1.60;P(X<50)=P(Z<1.60)==0.9452=94.52% (from z-table).
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