In a Science test, the mean score is 42 and the standard deviation is 5. Assuming the scores are normally distributed, what percent of the score is:
Less than 50?
We have a normal distribution, "\\mu=42, \\sigma=5."
Let's convert it to the standard normal distribution,
"z=\\cfrac{x-\\mu}{\\sigma}=\\cfrac{50-42}{5}=1.60;\\\\\nP(X<50)=P(Z<1.60)=\\\\\n=0.9452=94.52\\%\n\\text{ (from z-table).}"
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