a principal at a school.claims that the students in his school are above average intelligence. A random sample of forty student's IQ score have a mean of 112.5. the mean population IQ is 100 with a standard deviation of 15. use the 5% level of significance.
"H_0:a=100"
"H_1:a>100"
Test statistic: "T={\\frac {(112.5-100)*\\sqrt{40}} {15}}=5.27"
Since sample size is big, then it is appropriate to use Z-score as critical value, so
"P(Z>Cr)=0.05\\implies Cr=1.645"
We can see that T>Cr, so we should reject the null hypothesis and conclude that there is enough statistical evidence to aceept the fact that students IQ is greater than the mean
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