Question #325066

a principal at a school.claims that the students in his school are above average intelligence. A random sample of forty student's IQ score have a mean of 112.5. the mean population IQ is 100 with a standard deviation of 15. use the 5% level of significance.


1
Expert's answer
2022-04-08T04:03:32-0400

H0:a=100H_0:a=100

H1:a>100H_1:a>100

Test statistic: T=(112.5100)4015=5.27T={\frac {(112.5-100)*\sqrt{40}} {15}}=5.27

Since sample size is big, then it is appropriate to use Z-score as critical value, so

P(Z>Cr)=0.05    Cr=1.645P(Z>Cr)=0.05\implies Cr=1.645

We can see that T>Cr, so we should reject the null hypothesis and conclude that there is enough statistical evidence to aceept the fact that students IQ is greater than the mean


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