1. Find the value of the finite population correction factor when:
a) n = 10 and N = 10000
b) n = 40 and N= 10,000
a) FPC=N−nN−1=10000−1010000−1=99909999=0.99955.FPC=\sqrt{\cfrac{N-n}{N-1}}=\sqrt{\cfrac{10000-10}{10000-1}}=\sqrt{\cfrac{9990}{9999}}=0.99955.FPC=N−1N−n=10000−110000−10=99999990=0.99955.
b) FPC=N−nN−1=10000−4010000−1=99609999=0.99805.FPC=\sqrt{\cfrac{N-n}{N-1}}=\sqrt{\cfrac{10000-40}{10000-1}}=\sqrt{\cfrac{9960}{9999}}=0.99805.FPC=N−1N−n=10000−110000−40=99999960=0.99805.
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