Consider the composition of a 3-child family in which the children were born at different times but a girl is as likely as a boy at each birth. What is the probability that the oldest child and the youngest child are of the same gender?
Let's denote B for the birth of the boy and G for the birth of the girl.
There 8 possible outcomes:
BBB, BBG, BGB, GBB, BGG, GBG, GGB, GGG
The oldest child and the youngest child are of the same gender: BBB, BGB, GBG, GGG.
Therefore the probability that the oldest child and the youngest child are of the same gender is
"P = \\cfrac{4} {8} = \\cfrac{1} {2}."
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