Question #323987

A random variable X has a normal distribution with mean 45 and variance of 9.



Find the range of scores that lie:




a. within one standard deviation from the mean



b. within two standard deviations from the mean




1
Expert's answer
2022-04-06T09:32:47-0400

The mean μ=45,the standard deviation σ=9=3.\text{The mean }\mu=45,\text{the standard deviation }\sigma=\sqrt{9}=3.


a. The range of scores that lie within one standard deviation from the mean :

(μσ,μ+σ)=(453,45+3)=(42,48).(\mu-\sigma,\mu +\sigma)=(45-3,45+3)=(42,48).


b. The range of scores that lie within two standard deviations from the mean :

(μ2σ,μ+2σ)=(4523,45+23)=(39,51).(\mu-2\sigma,\mu +2\sigma)=(45-2\cdot3,45+2\cdot3)=(39,51).

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