A salesperson has found that the probability of a sale on a single contact is approximately .03. If the salesperson contacts 100 prospects, what is the approximate probability of making at least one sale?
P(X≥1)=1−P(0)=1−C1000(0.03)0(0.97)100=1−1x1x(0.97)100=1−0.05=0.95P(X \ge1)=1-P(0)=1-C^0_{100}(0.03)^0(0.97)^{100}=1-1x1x(0.97)^{100}=1-0.05=0.95P(X≥1)=1−P(0)=1−C1000(0.03)0(0.97)100=1−1x1x(0.97)100=1−0.05=0.95
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